Answer:
Angle of diffraction for second order maxima is θ = 18.941°
Explanation:
From the question it is given that
wavelength of incident light = λ = 541 nm = 541 x [tex]10^-^9 m[/tex]
order of maxima = n =2
diffraction grating has 600 lines per mm
⇒ distance between two slit is [tex]\frac{1mm}{600}[/tex] = 1.66 x [tex]10^-^6[/tex] m
using the relation of Braggs diffraction formula i.e.,
2dsinθ = nλ ..................................(1)
where, d = distance between two lines of grating
θ is the angle of diffraction
n= order of maxima
λ is the intensity of incident photon
on substituting the respected values in relation (1) we get,
2 x 1.66 x [tex]10^-^6[/tex]m sinθ = 2 x 541 x [tex]10^-^9 m[/tex]
⇒ sinθ = 0.3246
⇒ θ = [tex]sin^-^1(0.3246)[/tex] = 18.941 °
