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A wire is first bent into the shape of a square. Each side of the square is 9cm long. Then the wire is unbent and reshaped into a rectangle. If the length of the rectangle is 13cm, what is its width

Respuesta :

clarch19

Answer:

5 cm

Step-by-step explanation:

the perimeter of a square with sides of 9 cm is 36 cm so the rectangle must have the same perimeter

if the length of the rectangle is 13cm, its opposite side is also 13cm

add 13 + 13 to get 26

let 'n' = width of rectangle

perimeter = 26 + n + n

36 = 26 + 2n

2n = 10

n = 5

h8zy

Problem:

A wire is first bent into the shape of a square. Each side of the square is 9cm long. Then the wire is unbent and reshaped into a rectangle. If the length of the rectangle is 13cm, what is its width

Solution:

[tex]9 \times 4 - 13 \times 2[/tex]

[tex] = 36 - 26[/tex]

[tex] = 10[/tex]

Answer:

10 cm

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