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Answer:
C. f^-1(x) = (∛(x+1))/4
Step-by-step explanation:
The inverse function can be found by solving x = f(y) for y.
[tex]f(y)=x\\\\64y^3-1=x\\\\64y^3=x+1 \qquad\text{add1}\\\\4y=\sqrt[3]{x+1} \qquad\text{cube root}\\\\y=\dfrac{\sqrt[3]{x+1}}{4} \qquad\text{divide by 4}\\\\\boxed{f^{-1}(x)=\dfrac{\sqrt[3]{x+1}}{4}}[/tex]
