Respuesta :

clarch19

Answer:

(2h + 3k) (m -  n)

Step-by-step explanation:

factor by pairing:  pair and factor the first two terms, then pair and factor the remaining two; there should be one factor which duplicates

m is common factor of 1st pair: m(2h+3k)

n is common factor of 2nd pair: n(2h+3k)

answer is one of the duplicate factors (2h+3k) times terms not contained in parentheses (m+n)

mirai123

Answer:

[tex](2h+3k)(m-n)[/tex]

Step-by-step explanation:

[tex]2mh+3mk-2nh-3nk[/tex]

Just look at the common terms

[tex]2mh-2nh-3nk+3mk = 2h(m-n)-3k(n-m) = 2h(m-n)+3k(m-n)[/tex]

By grouping we have

[tex]2h(m-n)+3k(m-n) =\boxed{(2h+3k)(m-n)}[/tex]

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