Studying the decay of radioactive isotopes in dead organisms helps scientists to identify fossilized remains. The ratio of C-12 to C-14 in the atmosphere is 1 x 1012. The table shows this ratio inside the body of three organisms.

C12/C14 Ratio
Organism C12/C14 Ratio
X 8 x 1012
Y 2 x 1012
Z 1 x 1012

What can most likely be concluded from the above information?
Only Organism Z is alive, and Organism X has been dead longer than Organism Y.
Only Organism Z is alive, and Organism Y has been dead longer than Organism X.
Only Organism X is alive, and Organism Y has been dead longer than Organism Z.
Only Organism X is alive, and Organism Z has been dead longer than Organism Y.

After the death of an organism, there is radioactive disintegration of C-14 allotrope of carbon, which increases the ratio of C-12 to C-14 in a dead organism as compared to a living organism.

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abhishekprakash2625 abhishekprakash2625 · Answer 2 · 2021-12-21T16:31:31+01:00

The study of chemistry and its bond is called chemistry.

The correct answer is A

After the death of an organism, there is radioactive disintegration occurs which leads to the breakdown of C-14 allotrope of carbon into the other isotopes,

Breakdown of these isotopes leads to the increase in the ratio of C-12 to C-14 in a dead organism as compared to a living organism.

Hence, the correct answer is A that is Only Organism Z is alive, and Organism X has been dead longer than Organism Y.

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