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In an experiment, an object is heated.
The data from the experiment is shown.
The energy transferred to the object is 3.0 kJ.
The mass of the object is 2.0 kg.
The rise in temperature of the object is 10°C.
The specific heat capacity of the object is 150 J/(kg°C).
What is the thermal capacity of the object?
A 30J/°C
B 300 J/°C
C 3000J/°C D 9000 J/°C​

Respuesta :

xVenom32

Answer:

B) 300 J/°C

Explanation:

Q = 3kJ = 3000J

ΔT = 10°C

3000J/10°C = 300J/°C

To calculate heat capacity, use the formula: heat capacity = E / T, where E is the amount of heat energy supplied and T is the change in temperature.

E = 3kJ = 3000J

ΔT = 10°C

Heat capacity = E / T,

3000J/10°C = 300J/°C

What is heat capacity ?

"Heat capacity or thermal capacity is a physical property of matter, defined as the amount of heat to be supplied to an object to produce a unit change in its temperature." The SI unit of heat capacity is joule per kelvin. Heat capacity is an extensive property.

Know more about heat capacity here

https://brainly.com/question/13499849

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