Respuesta :
Answer:
[tex]perimeter = 2(l + w) \\ but \: length = 40 \times width \\ perimeter = 2(40w + w) \\ p = 2(41w) \\ 320 = 2(41w) \\ w = \frac{320}{(2 \times 41)} \\ w = 3.902 \: yards \\ length = 40 \times w \\ = 40 \times 3.902 \\ l = 156.08 \: yards[/tex]
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Answer:
- length: 100 yards
- width: 60 yards
Step-by-step explanation:
Let w represent the width of the field. Then the length is (w+40), and the perimeter is ...
P = 2(L +W)
320 = 2((w+40) +w) . . . . fill in values
160 = 2W +40 . . . . . . . . . divide by 2, collect terms
80 = w +20 . . . . . . . . . . . divide by 2
60 = w . . . . . . . . subtract 20
w+40 = 100
The length is 100 yards; the width is 60 yards.