Respuesta :

Answer:

[tex]consider \: triangle \: BDE \\m<BCD = m<BED \\ angles \: of \: triangle \: sum \: up \: to \: 180 ° \\ (14x + 4)° + 55° + 51° = 180° \\ 14x = 180° - (4 + 55 + 51)° \\ 14x = 70° \\ x = \frac{70}{14} \\ x = 5[/tex]

xVenom32

Answer:

x = 5

Step-by-step explanation:

all angles at corners in parallelogram must add to 360

bcd = 51 thus angle at opposite corner (bed) must also equal 51

adding = 51 + 51 = 102

angles at ebc and edc are also equal to each other

edf = 55 and cbf = 55

adding 55+55 = 110

360 - 110 - 102 = 148

divide by 2 for angles ebf and cfd

148/2 = 74

now solve

14x + 4 = 74

14x = 70

x = 5

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