Answer:
[tex]\% Be=36\%\\\\\% O=64\%[/tex]
Explanation:
Hello!
In this case, since the percent compositions of Be and O in beryllium oxide are computed as shown below:
[tex]\% Be=\frac{m_{Be}}{M_{BeO}} *100\%\\\\\% O=\frac{m_{O}}{M_{BeO}} *100\%[/tex]
Since atomic masses are respectively 9.01 and 16.0 g/mol and the molar mass of the compound is 25.01 g/mol, the resulting percent compositions are:
[tex]\% Be=\frac{9.01}{25.01} *100\%=36\%\\\\\% O=\frac{16.0}{25.01} *100\%=64\%[/tex]
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