Respuesta :

Space

Answer:

2 M

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Unit 0

  • Reading a Periodic Table
  • Using Dimensional Analysis

Aqueous Solutions

  • Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define

36.7 g CaF₂

300 mL H₂O

Step 2: Identify Conversions

Molar Mass of Ca - 40.08 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol

1000 mL = 1 L

Step 3: Convert

Solute

  1. Set up:                               [tex]\displaystyle 36.7 \ g \ CaF_2(\frac{1 \ mol \ CaF_2}{78.08 \ g \ CaF_2})[/tex]
  2. Multiply:                             [tex]\displaystyle 0.470031 \ mol \ CaF_2[/tex]

Solution

  1. Set up:                              [tex]\displaystyle 300 \ mL \ H_2O(\frac{1 \ L \ H_2O}{1000 \ mL \ H_2O})[/tex]
  2. Multiply:                            [tex]\displaystyle 0.3 \ L \ H_2O[/tex]

Step 4: Find Molarity

  1. Substitute [M]:                    [tex]\displaystyle x \ M = \frac{0.470031 \ mol \ CaF_2}{.3 \ L \ H_2O}[/tex]
  2. Divide:                                [tex]\displaystyle x = 1.56677 \ M[/tex]

Step 5: Check

Follow sig fig rules and round. We are given 1 sig fig as our lowest.

1.56677 M ≈ 2 M

Otras preguntas