Answer:
9.48 L.
Explanation:
Hello!
In this case, as the problem mentions a long way to solve it, we are going to apply it because it can provide the answer more rapidly; thus, considering that 112 km are required, 1 mile equals 1.609 km and 1 gallon equals 3.785 liters, we can set up the proportional factor as shown below:
[tex]112km*\frac{1mi}{1.609 km}*\frac{1gal}{27.8mi}*\frac{3.785L}{1gal}[/tex]
Whereas km, mi and gal are cancelled out as it turns out in L; therefore the required liters are:
[tex]9.48L[/tex]
Best regards!