What are all the exact solutions of square root 2 cosx-1=0 for 0 less than or equal to x less than or equal to 2 pi ?Give your answer in radians.

Answer: [tex]x=\frac{\pi}{4}\ or\ \frac{7\pi}{4}[/tex]
Step-by-step explanation:
Given equation is
[tex]\sqrt{2}\cos x-1=0[/tex]
solving this
[tex]\sqrt{2}\cos x=1\\\cos x=\frac{1}{\sqrt{2}}[/tex]
There can be two solution because [tex]0<x<2\pi[/tex]
[tex]\cos x=\cos \frac{\pi }{4}\ or\ \cos (2\pi -\frac{\pi}{4})\\[/tex]
so, [tex]x=\frac{\pi}{4}\ or\ \frac{7\pi}{4}[/tex]