9. Write a balanced nuclear equation for the following: The isotope Strontium-90 decays by Q-
decay (1 point)
OfSr — He +56 kr
OS → H +39 kr
o Sr + Be +38kr
99 Sr → He +3 Se
SAST +7+99 Sr

Respuesta :

Answer: [tex]_{38}^{90}\textrm{Sr}\rightarrow _{36}^{86}\textrm{Kr}+_2^4\textrm{He}[/tex]

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

General representation of an element is given as:   [tex]_Z^A\textrm{X}[/tex]

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

General representation of alpha decay :

[tex]_Z^A\textrm{Sr}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha[/tex]

The  balanced nuclear equation when the isotope Strontium-90 decays by Q-  decay is :

[tex]_{38}^{90}\textrm{Sr}\rightarrow _{36}^{86}\textrm{Kr}+_2^4\textrm{He}[/tex]