Respuesta :
Answer:
An equation of the line that passes through the point (6,−4) and is perpendicular to the line will be:
- [tex]y=-\frac{1}{2}x-1[/tex]
Step-by-step explanation:
We know that the slope-intercept form of the line equation
y = mx+b
where m is the slope and b is the y-intercept
Given the line
[tex]2x-y=5[/tex]
converting the line into slope-intercept form
y = 2x-5
comparing with the slope-intercept form of the line equation
The slope of the line = m = 2
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
slope = m = 2
Thus, the equation of new line = – 1/m = -1/2 = -1/2
using the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where m is the slope of the line and (x₁, y₁) is the point
substituting the values of the slope = -1/2 and the point (6,−4)
[tex]y-\left(-4\right)=-\frac{1}{2}\left(x-6\right)[/tex]
[tex]y+4=-\frac{1}{2}\left(x-6\right)[/tex]
Subtract 4 from both sides
[tex]y+4-4=-\frac{1}{2}\left(x-6\right)-4[/tex]
[tex]y=-\frac{1}{2}x-1[/tex]
Therefore, an equation of the line that passes through the point (6,−4) and is perpendicular to the line will be:
- [tex]y=-\frac{1}{2}x-1[/tex]
An equation of the line that passes through the point (6,−4) and is perpendicular to the line 2x−y=5 is [tex]y=-\frac{1}{2}x-1[/tex]
Given:
An equation of the line that passes through the point (6,−4) and is perpendicular to the line 2x−y=5
First we find the slope of given equation 2x-y=5
y=mx+b is the equation of the line . where 'm' is the slope
[tex]2x-y=5\\2x-5=y\\y=2x-5[/tex]
Slope m=2.
Slope of perpendicular lines are negative reciprocal of one another
Slope of perpendicular line is [tex]-\frac{1}{2}[/tex]
The line passes through the point (6,-4)
Use the point and slope to get the equation of the perpendicular line
slope m = [tex]-\frac{1}{2}[/tex]
Point slope form of line is
[tex]y-y_1=m(x-x_1)\\y+4=-\frac{1}{2}(x-6)\\y+4=-\frac{1}{2}x+3\\y=-\frac{1}{2}x-1[/tex]
An equation of the line that passes through the point (6,−4) and is perpendicular to the line 2x−y=5 is [tex]y=-\frac{1}{2}x-1[/tex]
Learn more : brainly.com/question/19864665
