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If all of be the simple the side lengths of a triangle had a length of 1 what would be the simplified laws of sines be?

If all of be the simple the side lengths of a triangle had a length of 1 what would be the simplified laws of sines be class=

Respuesta :

Answer:

sin A = sin B = sin C

Step-by-step explanation:

The sine rule is a law which relates all the three sides of a triangle with the sine of their opposite angles in the triangle. Given a triangle with a side of a and an opposite angle of A, side b with opposite angle B and side c with opposite angle C. The sine rule is given as:

[tex]\frac{sin(A)}{a}=\frac{sin(B)}{b}=\frac{sin(C)}{c}[/tex]

Given that all the side of the triangle have a length of 1, that is a = b = c = 1, hence the equation becomes:

[tex]\frac{sin(A)}{1}=\frac{sin(B)}{1}=\frac{sin(C)}{1}\\\\sin(A)=sin(B)=sin(C)[/tex]

Answer:

sin A = sin B = sin C

Step-by-step explanation:

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