Answer:
[tex]\boxed{\boxed{\pink{\bf The \ two \ numbers \ are \ 12 \& \ 85 . }}}[/tex]
Step-by-step explanation:
Given that , One number is 1 more than 7 times the other number. If their sum is 73 more than
twice the smaller number. And we need to find the numbers. So let us take the
- First Number be x .
- Second number be 7x+1 .
[tex]\underline{\red{\boldsymbol{ According \ to \ the \ Question :- }}}[/tex]
[tex]\bf\implies 2( Small \ no.) + 73 = Bigger \ no. + Smaller \ no.\\\\\bf\implies 2x + 73 = x + 7x + 1\\\\\bf\implies 2x + 73 = 8x + 1 \\\\\bf\implies 8x - 2x = 73-1 \\\\\bf\implies 6x = 72 \\\\\bf\implies x =\dfrac{72}{6} \\\\\bf\implies \boxed{\red{\bf x = 12 }}[/tex]
Hence the smaller number is 12 and the bigger number will be :-
[tex]\bf \implies Number_{bigger} = 7x + 1 \\\\\bf\implies Number_{bigger} =7(12)+1\\\\\bf\implies Number_{bigger} = 84 + 1 \\\\\bf\implies \boxed{\red{\bf Number_{bigger}=85 }}[/tex]
Hence the bigger number is 85 and the smaller number is 12.
