Answer:
45.375m
Explanation:
To get the distance travelled by the body we will use the equation of motion
S = ut + 1/2at²
u is the initial speed = 0m/s
a is the acceleration
t is the time = 5 seconds
We need to get the acceleration first:
According to Newton's second law,
[tex]\sum F_x = ma\\F_m - F_f = ma\\[/tex]
Fm is the moving force = Wsin theta
Ff is the frictional force = 1500N
m is the mass = W/g
m = 4000/9.8
m = 408.16kg
Substitute the given values in the formula and get the acceleration:
[tex]Wsin \theta - F_f = ma\\4000sin40^0 - 1500 = 408.16a\\2,980.45 - 1500 = 408.16a\\1,480.45 = 408.16a\\a = \frac{1,480.45}{408.16} \\a = 3.63m/s^2[/tex]
Get the required distance:
Recall that S = ut+1/2at²
S = 0(5) + 1/2*3.63*5²
S = 0+0.5*3.63*25
S = 45.375m
Hence the distance travelled by the body in 5 seconds if the force of friction is 1500N is 45.375m
