Given:
The equation is
[tex]\dfrac{3}{2}+b=\dfrac{7}{4}[/tex]
To find:
The value of b.
Solution:
We have,
[tex]\dfrac{3}{2}+b=\dfrac{7}{4}[/tex]
Subtracting both sides by [tex]\dfrac{3}{2}[/tex], we get
[tex]b=\dfrac{7}{4}-\dfrac{3}{2}[/tex]
[tex]b=\dfrac{7-2(3)}{4}[/tex]
[tex]b=\dfrac{7-6}{4}[/tex]
[tex]b=\dfrac{1}{4}[/tex]
Therefore, the value of b is [tex]\dfrac{1}{4}[/tex].
