Respuesta :
Answer:
You would put the 4 quantum numbers corresponding to the electrons being described above
Explanation:
Quantum numbers refer to electrons, so I'll assume you mean the electron number that would correspond with the atomic number of the element. Quantum numbers are basically like an address for electrons, giving us information about the location of an electron from most general to most specific.
The quantum selection rules allow finding the results for the quantum numbers for each electrons are:
1. n = 5, f l = 3 el m = 1
The quantum number of spin. Opposite the first electrons.
2. n = 4, l = 2, m = 0
Spin opposite the first electrons.
3. n = 4, l = 1, m = 0
Spin number opposite the first electrons.
4. n = 3, l = 1, m = 1
Spin all electrons have the same spin.
5. n = 7, l = 2, m = 0
Spin quantum number two electrons with opposite spin.
The solution of the Scrodinger's equation in three dimensions results have three constants related, these constants are called quantum numbers.
- Principal (n). Determines the energy of the electron and has values from zero to infinity.
- Secondary or orbital (l). Determines the shape of the orbitals and has values from zero to (n-1), in general letters are used for their representation for the values 0,1, 2, 3 the symbols are used: s, p, d, f.
- Magnetic (m). It corresponds to the magnetic moment due to the movement of the electron around the nucleus. It can have values from -l to l.
In independent experiments, a fourth quantum number called the spin magnetic moment was found, it can have two values + ½ and - ½
The rules for valid combinations of these quantum numbers are called selection rules, the spectroscope notation for each electron is.
[tex]n l ^m[/tex]
Where n is the principal number, l the orbital and m the magnetic.
To determine the value of the spin quantum number, the Pauli exclusion principle is used, which establishes that you cannot have two fermions (electrons) in the same quantum state, this deteriorates that in a state there can only be two electrons, one with upward spin and the other spin down.
Let's find the combination of these constants for each case.
1. The 11th electron of level 5f¹⁴.
The principal quantum number n = 5
Orbital quantum number f, l = 3
In the f orbital, a maximum of 14 electrons can be placed, since it has 7 sub-levels and according to the Pauli Exclusion principle, each one can have two electrons.
We place 1 electron in each sub-level and then we place a second electron with the opposite spin, therefore when we get to electron number 11 it has a spin opposite to that of the first 7 electrons, but there is no way to previously know its value.
we construct a table with the distribution of electrons.
Quantum number Electrons
n = 5
l = 0
l = 1
l = 2
l = 3
m = -3 ½ - ½
m = -2 ½ - ½
m = -1 ½ - ½
m = 0 ½ - ½
m = 1 ½
m = 2 ½
m = 3 ½
With the help of this table the other numbers are:
Tthe magnetic quantum number is m = 1
The quantum number of spin. opposite the spin of the first electrons.
2. The eighth electron of the 4d¹⁰ state
Pricipal number n = 4
Orbital number l = 2
We construct a table with the distribution of electrons.
Quantum number Electrons
n = 4
l = 0
l = 1
l = 2
m = -2 ½ - ½
m = -1 ½ - ½
m = 0 ½ - ½
m = 1 ½
m = 2 ½
With this table the other quantum numbers are;
Magnetic m = 0
Spin opposite the first electron
3. 5th electron of 4p⁶
Principal number n = 4
Orbital number p l = 1
We construct a table with the distribution of electrons.
Quantum number Electrons
n = 4
l = 0
l = 1
m = -1 ½ - ½
m = 0 ½ - ½
m = 1 ½
Magnetic number m = 0
Spin number opposite the first electrons.
4. 15th electron of phosphorus
The electron configuration of phosphor is
1s² 2s²2p⁶ 3s²3p³
Principal quantum number n = 3
Orbital quantum number p, l = 1
We construct the electron distribution table.
Quantum number electrons
n = 3
l = 0
l = 1
m = -1 ½
m = 0 ½
m = 1 ½
The other quantified numbers are:
Magnetic m = 1
Spin all electrons have the same spin.
5. The last electron of neptunium.
Electronic configuration.
Radon Gas Configuration + 5f⁴6d¹ 7s²
Principal quantum number n = 7
Orbital quantum number l = 2
Magnetic quantum number m = 0
Spin quantum number two electrons with opposite spin.
In conclusion using the quantum selection rules can determine the quantum numbers for each given electron are:
1. n = 5, f l = 3 el m = 1
The quantum number of spin. Opposite the first electrons.
2. n = 4, l = 2, m = 0
Spin opposite the first electrons
3. n = 4, l = 1, m = 0
Spin number opposite the first electrons.
4. n = 3, l = 1, m = 1
Spin all electrons have the same spin
5. n = 7, l = 2, m = 0
Spin quantum number two electrons with opposite spin.
Learn more about the quantum selection rules here: brainly.com/question/14288557
