Answer:
[tex]16^{2} (272)[/tex] is divisible by 17
Proof:
In order to solve this question we will have to factor [tex]16^{5} + 16^{4}[/tex]. We will have to do that as follows.
[tex]16^{5} + 16^{4} = 16^{3} (16^{2} + 16) = 16^{2} (272)[/tex]
From here we know the the resulting number will be equal to [tex]16^{2} (272)[/tex] now we will need to know the following property. If "b" is divisible by "c" then "ab" (where a is any integer) will also be divisible by c. In our case one of the factors is 272, and it is divisible by 17, so that means that [tex]16^{2} (272)[/tex] will also be divisible by 17.
