The line AB is shown on the grid.

b)Find the equation of the line
perpendicular to AB and passing
through the midpoint of AB.

The line AB is shown on the grid bFind the equation of the line perpendicular to AB and passing through the midpoint of AB class=

Respuesta :

Step-by-step explanation:

a)

first step: find the gradient slope of line AB

A(-1,-2) B(7,2)

gradient=change in y/change in x

M=[2-(-2)]/[7-(-1)

M=4/8

M=1/2

the gradient of the straight line is given by

M1*M2=-1

1/2*M2=-1

multiply both sides by the reciprocal of 1/2

2*1/2*M2=-1*2

M2= -2.

b)

first find the mind point of line AB

A(-1,-2) B(7,2)

M.P=(x1+x2)/2 ,(y+y2)/2

M.P=(-1+7)/2 ,(-2+2)/2

M.P=6/2 ,0/2

M.P=3,0

ALSO THE GRADIENT PERPENDICULAR TO LINE AB IS;

M= -2

equation of a line perpendicular to AB and passes through the midpoint of AB

Y-Y1=M(X-X1). (3,0). M=-2

y-0=-2(x-3)

y= -2x+6