Answer:
70.8m
Explanation:
Given parameters:
Time of fall = 3.8s
Unknown:
Depth of the mine = ?
Solution:
To solve this problem, we use the appropriate motion equation as shown below;
S = ut + [tex]\frac{1}{2}[/tex] at²
S is the depth
u is the initial velocity = 0m/s
t is the time taken
a is the acceleration due to gravity
Now insert the parameters and solve;
Since u = 0;
S = [tex]\frac{1}{2}[/tex] at² = [tex]\frac{1}{2}[/tex] x 9.8 x 3.8² = 70.8m
