Answer:
Efficiency = 5%
Explanation:
Given that,
Supplies energy to the bulb = 100 J
Transferred energy by the bulb = 5 J
We need to find the efficiency of the bulb. It can be given by "
[tex]\eta=\dfrac{\text{useful energy out}}{\text{useful energy in}}\times 100\\\\=\dfrac{5}{100}\times 100\\\\=5\%[/tex]
So, the efficiency of the bulb is 5%.
