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A company produces two different sizes of soup cans. The volume of the cans varies jointly with the square of the can's radius and the height. The smaller can has a height of 5 inches, a squared radius of 4 inches, and a volume of about 62.8 cubic inches. What is the volume of the taller can, which has a height of 9 inches and a squared radius of 4 inches? Round to the nearest tenth, as needed.
A. V=113.0
B. V=36.0
C. V=3.1
D. 91.3

Respuesta :

mhanifa

Answer:

  • A.  V= 113 in³

Step-by-step explanation:

Volume formula will be:

  • V = kr²h,

where V - volume, k - coefficient of proportion, r² - squared radius, h - height

Substitute the known values to find the unknown:

  • 62.8 = k*4*5
  • 62.8 = 20k
  • k = 62.8/20
  • k = 3.14

Now find the volume of the taller can:

  • V = kr²h
  • V = 3.14*4*9 = 113.04 ≈ 113 in³

Correct option is A

realdaneel

A=113.0

Hope it helps guys!! :)

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