Respuesta :
Answer:
15.1L
Explanation:
Given parameters:
Initial volume = 2.1L
Initial pressure = 3.6atm
Initial temperature = 200K
Final pressure = 1 atm
Final temperature = 400K
Unknown:
Final volume of the sample = ?
Solution:
To solve this problem, we are going to use the general gas law or the combined gas law which is expressed below:
[tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex]
P, V and T are pressure, volume and temperature
1 and 2 are the initial and final states
Now;
[tex]\frac{2.1 x 3.6}{200}[/tex] = [tex]\frac{1 x V_{2} }{400}[/tex]
200V₂ = 3024
V₂ = 15.1L
Answer:
15.1L
Explanation:
Given parameters:
Initial volume = 2.1L
Initial pressure = 3.6atm
Initial temperature = 200K
Final pressure = 1 atm
Final temperature = 400K
Unknown:
Final volume of the sample = ?
Solution:
To solve this problem, we are going to use the general gas law or the combined gas law which is expressed below:
P, V and T are pressure, volume and temperature
1 and 2 are the initial and final states
Now;
=
200V₂ = 3024
V₂ = 15.1L