URGENT!! Can someone help me with this?

A sample of oxygen gas has a volume of 2.1 L at 3.6 atm pressure and 200 K temperature.

What would the volume of this sample be at 1.0 atm and 400 K?

Respuesta :

Answer:

15.1L

Explanation:

Given parameters:

Initial volume  = 2.1L

Initial pressure = 3.6atm

Initial temperature  = 200K

Final pressure  = 1 atm

Final temperature  = 400K

Unknown:

Final volume of the sample  = ?

Solution:

To solve this problem, we are going to use the general gas law or the combined gas law which is expressed below:

           [tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex]

P, V and T are pressure, volume and temperature

1 and 2 are the initial and final states

Now;

        [tex]\frac{2.1 x 3.6}{200}[/tex]   = [tex]\frac{1 x V_{2} }{400}[/tex]  

          200V₂  = 3024

                 V₂ = 15.1L

Answer:

15.1L

Explanation:

Given parameters:

Initial volume  = 2.1L

Initial pressure = 3.6atm

Initial temperature  = 200K

Final pressure  = 1 atm

Final temperature  = 400K

Unknown:

Final volume of the sample  = ?

Solution:

To solve this problem, we are going to use the general gas law or the combined gas law which is expressed below:

         

P, V and T are pressure, volume and temperature

1 and 2 are the initial and final states

Now;

          =  

         200V₂  = 3024

                V₂ = 15.1L