A tired squirrel (mass of approximately 1 kg) does push-ups by applying a force to elevate its center-of-mass by 5 cm in order to do a mere 0.50 Joule of work. If the tired squirrel does all this work in 2 seconds, then determine its power.

Respuesta :

Answer:

Power = 0.25 Watts

Explanation:

Given:

Work done = 0.50 Joule of work

Time taken = 2.0 second

Find:

Power

Computation:

Power = Work done / Time taken

Power = 0.50 J / 2

Power = 0.25 Watts