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An AC voltage source, with a peak output of 200 V, is connected to a 50-Ohm resistor. What is the effective (or rms) current in the circuit

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pstnonsonjoku

Answer:

2.8 A

Explanation:

We know that;

Vrms = Vo/√2

Where;

Io = peak value of voltage = 200V

Hence;

Irms = 0.707 × 200

Irms = 141.4 V

Irms = Vrms/R = 141.4/50 = 2.8 A

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