Answer:
We must duplicate the length of the rope (R'=2R) to get
[tex]F'=\frac{1}{2}F[/tex]
Explanation:
The equation of the centripetal force is given by:
[tex]F_{c}=ma_{c}[/tex]
[tex]F_{c}=m\frac{v^{2}}{R}[/tex]
Where:
R is the length of the rope
m is the mass of the object
v is the speed of the object
If we want to reduce the centripetal force in half, we can duplicate the length of the rope (R'=2R), which means:
[tex]F'_{c}=m\frac{v^{2}}{R'}[/tex]
[tex]F'_{c}=m\frac{v^{2}}{2R}[/tex]
[tex]F'_{c}=\frac{1}{2}F_{c}[/tex]
I hope it helps you!
