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Calculate the average rate of decomposition of NH4NO2 by the reaction 2NH4O5(aq) --> N2(g) H2O(g) at the following time interval. At time 250 s, the concentration of NH4NO2 is 4.12 M. At time 330 s, the concentration of NH4NO2 is 1.48 M

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Answer:

[tex]r=-0.033\frac{M}{s}[/tex]

Explanation:

Hello!

In this case, since the average rate of reaction is computed as a change given by:

[tex]r=\frac{\Delta [NH_4NO_2 ]}{\Delta t}[/tex]

In such a way, given the concentrations at the specified times, we plug them in to obtain:

[tex]r=\frac{(1.48M-4.12M)}{(330s-250s)}\\\\r=-0.033\frac{M}{s}[/tex]

Whose negative sign means the concentration decreased due to the decomposition.

Best regards!

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