Answer:
[tex]K'=\frac{1}{16}[/tex]
Explanation:
Hello!
In this case, since the given reaction is:
[tex]A+ 2B \rightleftharpoons C+ \frac{5}{2} D[/tex]
Whereas the equilibrium constant is:
[tex]K=\frac{[C][D]^{5/2}}{[A][B]^2} =4.0[/tex]
However, the new target reaction reverses and doubles the initial reaction to obtain:
[tex]2C+5D \rightleftharpoons 2A+4B[/tex]
Whereas the equilibrium constant is:
[tex]K'=\frac{[A]^2[B]^4}{[C]^2[D]^5}[/tex]
Which suggest the following relationship between the equilibrium constants:
[tex]K'=\frac{1}{K^2}[/tex]
So we plug in to obtain:
[tex]K'=\frac{1}{4.0^2}\\\\K'=\frac{1}{16}[/tex]
Best regards!
