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A chemist must prepare 575.mL of 1.00M aqueous sodium carbonate Na2CO3 working solution. He'll do this by pouring out some 1.58M aqueous sodium carbonate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the sodium carbonate stock solution that the chemist should pour out. Round your answer to 3 significant digits.

Respuesta :

Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.

Explanation :

According to dilution law:

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of aqueous sodium carbonate

[tex]M_2[/tex] = molarity of aqueous sodium carbonate stock solution

[tex]V_1[/tex] = volume of aqueous sodium carbonate

[tex]V_2[/tex] = volume of aqueous sodium carbonate stock solution

Given:

[tex]M_1[/tex] = 1.00 M

[tex]M_2[/tex] = 1.58 M

[tex]V_1[/tex] = 575 mL

[tex]V_2[/tex] = ?

Now put all the given values in the above formula, we get:

[tex]1.00M\times 575mL=1.58M\times V_2[/tex]

[tex]V_2=363.92mL\approx 364mL[/tex]

Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.

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