Given that,
An equation : -9c² +2c +3 = 0
To find,
Find the value of x.
Solution,
We have, -9c² +2c +3 = 0
We can solve it using the formula as follows :
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
Here, a = -9, b = 2 and c =3
Put the values,
[tex]c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69[/tex]
So, the solution are -0.47 and 0.69.
