10. Find the width of the canyon.
13.
width = ?
22 m
15 m
160 m
I need help asap

Answer:
Therefore, the width of the canyon is 109.09 meters.
Step-by-step explanation:
* 160/22 = k (Scale Factor)
7.2727 = k
* Let x be the width of the canyon
x / 15 = k
x / 15 = 7.2727
x = 7.2727 (15)
x = 109.09 m
The width of the canyon is 109.09m.
Here we assume x be the width of the canyon.
The k(Scale factor) should be
= [tex]160 \div 22[/tex]
k = 7.2727
So,
[tex]x \div 15 = k\\\\ x \div 15 = 7.2727[/tex]
x = 109.09 m
Learn more: brainly.com/question/17429689