1. Heat needed = 293.25 J
2. Time to leave : 2 s
Further explanation
Given
1.5 g H2
Cp H2 = 14.27 g/J C
Δt= 13.7
Required
1. Heat needed
2. Fridge time
Solution
1. Heat can be formulated :
Q = m.c.Δt
Q = 1.5 x 14.27 x 13.7
Q = 293.25 J
2. Heat decreases = 150 J/s, so for 293.25 J :
[tex]\tt t=\dfrac{293.25~J}{150~J/s}=1.955~s\approx 2~s[/tex]
