Two triangles are similar. The smaller triangle has side lengths 10, 20, and 15 units. The larger triangle's longest side is 52 units. What is the perimeter of the larger triangle?

Respuesta :

Answer:

117 units

Step-by-step explanation:

if you use the ratio of the two longest sides then you can find all side lengths

[tex]\frac{52}{20}[/tex] = [tex]\frac{x}{10}[/tex];    x = half of 52, or 26

[tex]\frac{52}{20}[/tex] = [tex]\frac{x}{15}[/tex];    20x = 52 · 15

              20x = 780

               x = 39

add to get perimeter: 52 + 26 + 39 = 117 units

Perimeter of the larger triangle is 117 units

Given

Two triangles are similar. The smaller triangle has side lengths 10, 20, and 15 units.

When the triangles are similar then the sides are in proportion

the longest side of the smaller triangle is 20 units

The larger triangle's longest side is 52 units.

Lets find out the unknown sides of largest triangle

Let x  and  y be the unknown sides . Make a proportion and solve for x  and y

[tex]\frac{52}{20}=\frac{x}{10} \\x=\frac{52}{20} \codt 10\\x=26\\\\\\\frac{52}{20}=\frac{y}{15}\\y=\frac{52}{20} \codt 15\\y=39[/tex]

The unknown sides of largest triangle is 26 and 39 units

To find out the perimeter add all the sides of largest triangle

Perimeter =[tex]26+39+52=117[/tex]

Perimeter of the larger triangle is 117 units

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