Respuesta :

gmany

Answer:

[tex]\huge\boxed{x\approx11.1}[/tex]

Step-by-step explanation:

Use cosine:

[tex]cosine=\dfrac{adjacent}{hypotenuse}[/tex]

We have:

[tex]adjacent=x\\\\hypotenuse=15\\\\\theta=42^o[/tex]

Substitute:

[tex]\cos42^o=\dfrac{x}{15}\\\\\cos42^o\approx.7431\\\\\dfrac{x}{15}=0.7431\qquad|\text{multiply both sides by 15}\\\\15\!\!\!\!\!\diagup\cdot\dfrac{x}{15\!\!\!\!\!\diagup}=15\cdot0.7431\\\\x=11.1465\\\\x\approx11.1[/tex]

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