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What pressure would be required to take 100.0ml of a gas at 103.0kPa and squish it down to 2.00ml, assuming temperature and number of moles is held constant?

Respuesta :

ardni313

The pressure required = 5150 kPa

Further explanation

Given

V₁ = 100 ml

P₁ = 103 kPa

V₂= 2 ml

Required

Pressure

Solution

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

[tex]\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}[/tex]

[tex]\tt P_2=\dfrac{P_1.V_1}{V_2}\\\\P_2=\dfrac{103\times 100}{2}\\\\P_2=5150~kPa[/tex]

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