Part A)
Given
Using the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where
m is the slope of the line
(x₁, y₁) is the point
In our case:
substituting the values m = 6 and the point (x₁, y₁) = (7, 2) in the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y - 2 = 6(x-7)[/tex]
Therefore, the equation in point-slope form for the line having the slope m = 6 and containing the points (7,2) will be:
[tex]y - 2 = 6(x-7)[/tex]
Part B)
Given
Using the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where
m is the slope of the line
(x₁, y₁) is the point
In our case:
substituting the values m = -3 and the point (x₁, y₁) = (3, 8) in the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y - 8 = -3(x-3)[/tex]
Therefore, the equation in point-slope form for the line having the slope m = -3 and containing the points (3, 8) will be:
[tex]y - 8 = -3(x-3)[/tex]