There are 10.97 moles of NaCl in 2.35 liters of a 4.67 M solution.
no. of moles = volume × molarity
no of moles = 2.35L × 4.67M
no of moles = 10.97mol
Therefore, there are 10.97 moles of NaCl in 2.35 liters of a 4.67 M solution.
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