Answer:
4[tex]\frac{7}{12}[/tex]
Step-by-step explanation:
Give make the fractions improper first!
3[tex]\frac{1}{4}[/tex] -> [tex]\frac{13}{4}[/tex]
1[tex]\frac{1}{3}[/tex] -> [tex]\frac{4}{3}[/tex]
Now give them the same denominator, making it easy to solve.
[tex]\frac{13(3)}{4(3)}[/tex] -> [tex]\frac{39}{12}[/tex]
[tex]\frac{4(4)}{3(4)}[/tex] - >[tex]\frac{16}{12}[/tex]
now add!
[tex]\frac{55}{12}[/tex] - > 4[tex]\frac{7}{12}[/tex]
