Respuesta :

Answer:

we have the expression as;

1/sin u cos u

Step-by-step explanation:

tan u = sin u/cos u

cot u = cos u/sin u

Thus;

sin u/cos u + cos u/sin u

The lcm is sin u cos u

Thus, we have that;

(sin^2 u + cos^2 u)/sin u cos u

But ; sin^2 u + cos^2 u = 1

so we have ;

1/sin u cos u

adioabiola

The requested trigonometric expression in terms of sine and cosine is;

[tex]f(u) = \frac{1}{ \frac{sinu}{cosu} + \frac{cosu}{sinu} } [/tex]

Trigonometric expressions:

We must remember,

  • tan u = sin(u)/cos(u)

  • and cot u = cos(u)/sin(u).

Therefore we have;

sin(u)/cos(u) + cos(u)/sin(u) = 1/f(u)

By Cross-product; we have;

[tex]f(u) = \frac{1}{ \frac{sinu}{cosu} + \frac{cosu}{sinu} } [/tex]

Therefore, the required function, f(u) in terms of sin u and cos u is as represented above.

Read more on trigonometry;

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