Mass of Nitrogen= 42 grams
Further explanation
Given
one mole of Sodium azide
Required
mass of Nitrogen
Solution
Reaction
The decomposition of one mol of sodium azide :
2
N
a
N
3
(
s
)
→
2Na
(
s
)
+
3
N2
(
g
)
From the equation, the mol ratio of N
a
N
3
(
s
) : N2
(
g
) = 2 : 3, so mol N2 :
= 3/2 x mol N
a
N
3
= 3/2 x 1
= 1.5 moles
Mass of Nitrogen
= mol x molar mass
= 1.5 x 28 g/mol
= 42 grams
