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Find the equation of a line that passes through the point (4,2) and has a gradient of 5.
Leave your answer in the form y = mx + c

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Answer:

The equation of a line in the slope-intercept form is:

y = 5x - 18

Step-by-step explanation:

The slope-intercept form of the line equation

[tex]y = mx+b[/tex]

where

  • m is the slope
  • b is the y-intercept

In our case, we are given

  • m = 5
  • Point (4, 2)

now substituting m = 5 and (4, 2) in the slope-intercept form of the line equation to determine the y-intercept

y = mx + b

2 = 5(4) + b

20 + b = 2

subtract 20 from both side

20 + b - 20 = 2 - 20

b = -18

now substituting b = -18 and m = 5 in the slope-intercept form of the line equation

y = mx + b

y = 5x + (-18)

y = 5x - 18

Therefore, the equation of a line in the slope-intercept form is:

y = 5x - 18

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