The net ionic equation for the reaction between SnSO₄ and NaOH is:
Sn²⁺(aq) + 2OH¯(aq) —> Sn(OH)₂(s)
We'll begin by writing the dissociation equation for SnSO₄ and NaOH.
SnSO₄(aq) —> Sn²⁺(aq) + SO₄²¯(aq)
NaOH(aq) —> Na⁺(aq) + OH¯(aq)
In solution, the reaction will proceed as follow:
SnSO₄(aq) + NaOH(aq) —>
Sn²⁺(aq) + SO₄²¯(aq) + Na⁺(aq) + OH¯(aq) —> Sn(OH)₂(s) + Na⁺(aq) + SO₄²¯(aq)
Cancel the spectator ions (i.e Na⁺ and SO₄²¯) and write 2 before OH¯ to obtain the net ionic equation.
Sn²⁺(aq) + 2OH¯(aq) —> Sn(OH)₂(s)
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