Answer:
Approximately 92 mm.
Explanation:
Object's distance, u = 110 mm = 11 cm
focal length of the mirror = 5 cm
Image distance, v = ?
To determine the image distance, apply the mirror's formula;
[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{u}[/tex] + [tex]\frac{1}{v}[/tex]
[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{f}[/tex] - [tex]\frac{1}{u}[/tex]
= [tex]\frac{1}{5}[/tex] - [tex]\frac{1}{11}[/tex]
= [tex]\frac{11-5}{55}[/tex]
[tex]\frac{1}{v}[/tex] = [tex]\frac{6}{55}[/tex]
⇒ v = [tex]\frac{55}{6}[/tex]
= 9.166667
v = 9.2 cm
The image distance is 92 mm.
