Answer:
[tex]1=\frac{1}{3} x+1[/tex]
Step-by-step explanation:
Find the slope of (0, 1) and (2,-5)
[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
[tex]\frac{-5-1}{2-0}[/tex]
[tex]\frac{-6}{2}[/tex], or -3
Using point-slope form ([tex]y-y_{1}=m(x-x_{1})[/tex])
[tex]y-1=\frac{1}{3} (x-0)\\y-1=\frac{1}{3}x\\y=\frac{1}{3} x+1[/tex]
(note: one-third is the inverse of -3)
