Answer:
the velocity of the brick when it hits the ground is 39.60 m/s
Explanation:
Given;
height through which the ball is dropped, h = 80.0 m
the initial velocity of the brick, u = 0
The final velocity of the brick when it hits the ground is calculated as;
v² = u² + 2gh
v² = 0 + 2 x 9.8 x 80
v² = 1568
v = √1568
v = 39.60 m/s
Therefore, the velocity of the brick when it hits the ground is 39.60 m/s
