Answer:
the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
Explanation:
Given;
applied force, F = 5000 N
cross sectional area of the steel wire, A = 0.2 m²
The tensile stress of the steel wire, is calculated as;
[tex]\sigma = \frac{F}{A} \\\\\sigma = \frac{500}{0.2} \\\\\sigma = 2500 \ N/m^2\\\\\sigma = 2.5 \ \times \ 10^3 \ Nm^{-2}[/tex]
Therefore, the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
