Answer:
The velocity of the balloon at the bottom is 19.99 m/s.
Explanation:
Given;
mass of water balloon, m = 3.7 kg
height of fall, h = 20.38 m
The velocity of the balloon at the bottom is calculated from the law of conservation of energy;
[tex]K.E_{bottom} = P.E _{top}[/tex]
[tex]\frac{1}{2}mv^2 = mgh \\\\ v^2 = 2gh\\\\v= \sqrt{2gh} \\\\v = \sqrt{2\times 9.8 \times 20.38} \\\\v = 19.99 \ m/s[/tex]
Therefore, the velocity of the balloon at the bottom is 19.99 m/s.
