The time taken will be "0.5 seconds".
According to the question,
By using Newton's equation,
→ [tex]s = ut+\frac{1}{2}gt^2[/tex]
Substituting the values,
[tex]48=88t+0.5\times 32\times t^2[/tex]
[tex]16t^2+886-48=0[/tex]
[tex]t = 0.5 \ seconds[/tex]
Thus the above solution is right.
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